How to print first row of a file as a list?

Question

I need to grab the first row of a .csv file (the headers), and return it as a list.

I tried something like this:

import csv
with open('some.csv', 'rb') as f:
    reader = csv.reader(f)
    for row in reader:
        print row

But it prints the entire csv file. I was also thinking of just breaking the for loop immediately after printing the first row, but I didn't think that was the most efficient way to do it.

Is there a better way?

just add `break` after the `print` – Avinash Raj Sep 20 '15 at 06:22 — Avinash Raj, Sep 20 '15 at 06:22
using `reader[0]`, `reader[1]` ... – ZdaR Sep 20 '15 at 06:22 — ZdaR, Sep 20 '15 at 06:22

score 1 · Answer 1 · answered Sep 20 '15 at 06:23

1

Since csv.reader object upports the iterator protocol you can simply call the next function on it to get the first item :

reader = csv.reader(f)
print next(reader)

answered Sep 20 '15 at 06:23

Mazdak

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How to print first row of a file as a list?

1 Answers1