Call default interface method which is overridden in superclass

Question

I have a interface and abstract class.

public class TEST extends Abstract implements Inter2{
    void print() {
        toDO();
    }

    public static void main(String[] args) {
        new TEST().toDO();
    }
}

abstract class Abstract {

    public void toDO() {
        System.out.println("Abstract is called");
    }
}

interface Inter2 {

    default void toDO() {
        System.out.println("Inter2 is called");
    }
}

I want to force class interface default methods instead of abstract class.

http://stackoverflow.com/a/32478021/2775450 – Codebender Sep 11 '15 at 06:07 — Codebender, Sep 11 '15 at 06:07

score 7 · Accepted Answer · answered Sep 11 '15 at 06:07

7

You'll have to override toDO in the TEST class:

@Override
public void toDO() {
    Inter2.super.toDO();
}

answered Sep 11 '15 at 06:07

JB Nizet

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Java is quite logical here - for you can implement multiple interfaces, that is why you have to prefix super. If super is alone, then it refers to the only one superclass that can be extended. – gilyen Jun 13 '22 at 06:30

Call default interface method which is overridden in superclass

1 Answers1