romove last 5 character of string in Unix

Question

I need to trim last 8 character of a file name
Example:

Input -Vignesh.dat12345678
expected o/p : Vignesh.dat

I tried using rev but it didn't worked.

Give us your code... – Merlí Escarpenter Pérez Sep 01 '15 at 07:22 — Merlí Escarpenter Pérez, Sep 01 '15 at 07:22

score 0 · Answer 1 · answered Sep 01 '15 at 07:31

Your question says that you need to remove 5 characters, while the description says 8 !!!

Standard Format-

echo Vignesh.dat12345678 | rev | cut -c X- | rev

Assuming you want to remove 8 characters,

echo Vignesh.dat12345678 | rev | cut -c 9- | rev

The above code will remove last 8 characters. To remove n characters, simply put (n+1) instead of X.

1 Answers1