Converting NSArray to NSMutableArray

Question

As above. Would be helpful to know. Thanks!

adding "need this urgently" is likely to have the opposite effect... — Mitch Wheat, Jul 11 '10 at 06:40
This is like the third exact question on NSArray and NSMutableArray's today. — Anurag, Jul 11 '10 at 07:10

score 85 · Accepted Answer · answered Sep 02 '11 at 18:26

85

Here are two options:

- (NSMutableArray *)createMutableArray1:(NSArray *)array
{
    return [NSMutableArray arrayWithArray:array];
}

- (NSMutableArray *)createMutableArray2:(NSArray *)array
{
    return [[array mutableCopy] autorelease];
}

answered Sep 02 '11 at 18:26

Cameron Spickert

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Here's a conversion back to an NSArray: NSArray *array = [NSArray arrayWithArray:mutableArray]; – Nick N Sep 05 '14 at 22:52

Fabian Kreiser · Answer 2 · 2013-02-11T12:11:41.137

18

Use -mutableCopy and make sure to balance the retain count.

NSMutableArray *mutableArray = [[immutableArray mutableCopy] autorelease];

edited Feb 11 '13 at 12:11

answered Sep 02 '11 at 18:22

Fabian Kreiser

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It's now: NSMutableArray *mutableArray = [immutableArray mutableCopy]; – Marcel Marino Jun 18 '15 at 15:54
@MarcelMarino That's correct! – falkon21 May 13 '16 at 10:05

score 11 · Answer 3 · edited Apr 28 '14 at 23:44

11

Try this one

NSMutableArray *array = [[NSMutableArray alloc]initWithArray:your_array_name];

edited Apr 28 '14 at 23:44

SSteve

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answered Feb 12 '13 at 09:00

dhaya

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Converting NSArray to NSMutableArray

3 Answers3

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