I have the following code which is parsing an XML file in PowerShell, and then iterating through the entries in the config file (which are backup jobs) and performing backups (by calling functions).
if ($xmlfile.configuration.DBAndFilesBackup.item("MSSQL").haschildnodes) {
$xmlfile.configuration.DBAndFilesBackup.MSSQL.backup |
Start-RSJob -Name {$_.Name} -Throttle 2 -ScriptBlock {
# Begin the Backup
BeginBackup $_.Name $log
# Backup the mssql database
MSSQLBackup $_.Name $_.DBPath $Using:backupdir $Using:backuptempdir
# Backup the files
FilesBackup $_.Name $_.FolderName $_.FilesPath $Using:backupdir $Using:backuptempdir
# End the Backup
EndBackup $_.FolderName $_.Name $log $Using:emailTo $Using:backupdir $Using:backuptempdir
} -FunctionsToLoad BeginBackup,MSSQLBackup,FilesBackup,EndBackup,Mailer,PrintHeader |
Wait-RSJob |
Receive-RSJob |
Out-file "$ScriptDir\logs\corebackup\$ScriptName $($xmlfile.configuration.DBAndFilesBackup.MSSQL.backup.Name) $DateStamp.log"
}
Start-RSJob
is a custom PowerShell module similar to the Start-Job
cmdlet that handles kicking off parallel jobs.
Both RSJob and the native PowerShell Start-Job
cmdlet don't seem to handle PowerShell transcription (logging). Thus I'm utilizing Write-Output
, in addition to Out-File
to capture the output of the jobs.
The problem I've run into is that in the Write-Output
portion of the script I want to include the name of the backup in the log file name. In other words I end up with a file named "corebackup 2015-08-24.log" instead of "corebackup backupname 2015-08-24.log".
The issue is how do I pass $_.Name
to Out-File
. Right now a log is written, but without the job name.