26

Okay so i have the following code:

    var element = document.getElementById(scope.changeid);

function getData(division,redraw) {
    var employeeData = [];
    if (!division) {
        $http.get(api.getUrl('competenceUserAverageByMyDivisions', null)).success(function (response) {
            processData(response,redraw);
        });
    }
    else {
        $http.get(api.getUrl('competenceUserAverageByDivision', division)).success(function (response) {
            processData(response,redraw);
        })
    }

}

function processData(data,redraw) {
    var y = [],
        x1 = [],
        x2 = [];

    data.forEach(function (item) {
        y.push(item.user.profile.firstname);
        x1.push(item.current_level);
        x2.push(item.expected);
    });

    var charData = [{
            x: x1,
            y: y,
            type: 'bar',
            orientation: 'h',

            name: 'Nuværende'
        }, {
            x: x2,
            y: y,
            type: 'bar',
            orientation: 'h',

            name: 'Forventet'
        }],
        layout = {
            barmode: 'stack',
            legend: {
                traceorder: 'reversed',
                orientation: 'h'

            }
        };

    if(!redraw){
        Plotly.plot(element, charData, layout);
    }
    else
    {
        Plotly.redraw(element,charData,layout);
    }
}

scope.$watch('divisionId', function (newValue, oldValue) {
    if (newValue) {
        getData(newValue.id,true);
    }
}, true);

getData(null,false);

Which creates the following chart:

enter image description here

Now as you can see ive added a watcher

            scope.$watch('divisionId', function (newValue, oldValue) {
            if (newValue) {
                getData(newValue.id,true);
            }
        }, true);

Now when i trigger this it should update the chart and call Plotly.redraw(element,charData,layout);

However when it does this the chart does not change at all. There is no error in the console so i am not quite sure what to do?

Christophe Roussy
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Marc Rasmussen
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4 Answers4

21

Plotly.redraw(gd) is the right way.
But you call Plotly.redraw incorrectly.
The right way is update the data object, instead of new a data object.

var data = [{
    x: ['VALUE 1'], // in reality I have more values... 
    y: [20], 
    type: 'bar'
}]; 
Plotly.newPlot('PlotlyTest', data);
function adjustValue1(value) {
    data[0]['y'][0] = value; 
    Plotly.redraw('PlotlyTest');
}

Ref: http://www.mzan.com/article/35946484-most-performant-way-to-update-graph-with-new-data-with-plotly.shtml

Falko
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Honghe.Wu
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17

I found the answer to the question.

Apprently i needed to use:

 Plotly.newPlot(element,charData,layout);

instead of redraw

Marc Rasmussen
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4

According to a Plotly community moderator (see the first answer here), Plotly.restyle is faster than Plotly.redraw and Plotly.newPlot.

Example taken from the link:

var data = [{
    x: ['VALUE 1'], // in reality I have more values...
    y: [20],
    type: 'bar'
}];
Plotly.newPlot('PlotlyTest', data);

function adjustValue1(value)
{
    Plotly.restyle('PlotlyTest', 'y', [[value]]);
}
Safwan
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1

The extendTraces function should be what you are aiming for. It can add data points to your graph and redraws it. In contrast to redraw (@Honghe.Wu Answer), you do not need to update the reference when using extendTraces.

[extendTraces] This function has comparable performance to Plotly.react and is faster than redrawing the whole plot with Plotly.newPlot.

https://plot.ly/javascript/plotlyjs-function-reference/#plotlyextendtraces

Example usage

// initialise some data beforehand
var y = [];
for (var i = 0; i < 20; i ++) {
    y[i] = Math.random();
}

var trace = {
    // x: x,
    y: y,
    type: 'bar',
  };
var data = [trace];
// create the plotly graph
Plotly.newPlot('graph', data);

setInterval(function() {
  // add data to the trace via function call
  Plotly.extendTraces('graph', { y: [[getData()]] }, [0]);
  // y.push(getData()); Plotly.redraw('graph'); //similar effect
}, 400);

function getData() {
     return Math.random();
}
Andrei
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