How do I return an array containing the digits of the initial number

Question

Given a non-negative integer, I need to return an array containing the digits of the initial number, considering that the initial number shall be less than 100,000. For example:

separateDigits(93) → {9, 3}
separateDigits(125) → {1, 2, 5}
separateDigits(732) → {7, 3, 2}

How do I separate the digits?

What have you tried and what are you having trouble with? Do you know how to write a function, create an array, divide by 10? — Peter Lawrey, Aug 18 '15 at 06:24

score 0 · Answer 1 · answered Aug 18 '15 at 06:28

0

You need to create an array but first you need to know how big. Then you need to fill the array with digits.

public byte[] separateDigits(long n) {
    int digits = 1; 
    for(long m = n; (m /= 10) > 0; digits++);

    byte[] ret = new byte[digits];
    for(int i = digits - 1 ; i >= 0; i--, n /= 10)
        ret[i] = (byte) (n % 10);
    return ret;
}

answered Aug 18 '15 at 06:28

Peter Lawrey

525,659
79
751
1,130

Peter Lawrey, this is the method preset for this problem: public int[] separateDigits(int num) { – user5183901 Aug 18 '15 at 15:59
So I can't use byte [] or long n – user5183901 Aug 18 '15 at 16:00

score 0 · Answer 2 · answered Aug 19 '15 at 11:31

//this might help you

import java.util.*;
public class SeparaeDigits {

    public static void main(String[] args) {
        int num =123;
     seperateDigits(num);


    }
    public static void seperateDigits(int num){
        int i=0;
        int remainder =0;
        int []arr = new int[3];
while(num>0){
 remainder = num % 10;
num = num/10;
for(i =0; i<arr.length; i++){
    arr[i]=remainder;

}
for(i =0; i<arr.length; i++){
System.out.println(arr[i]);
}

}
}
}

How do I return an array containing the digits of the initial number

2 Answers2