Get the integral part of a BigFraction, as a BigInteger

Question

What is an easy way to get the integral part of a BigFraction as a BigInteger?

Basically I want the same result that the intValue and longValue methods return but with arbitrary precision.

I also want to avoid rounding so indirect conversion via a BigDecimal is not suitable.

I need the BigFraction Object, but can't find the jar files online. where do you get it? thx. — SecureFish, Mar 21 '11 at 04:39
@SecureFish, http://commons.apache.org/math/download_math.cgi — finnw, Mar 21 '11 at 15:15

score 3 · Accepted Answer · answered Jul 08 '10 at 14:41

3

myBigFraction.getNumerator().divide( myBigFraction.getDemoninator() );

?

answered Jul 08 '10 at 14:41

mob

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Unsurprisingly `BigFraction.longValue()` is implemented this way. The surprising part is that there is no `bigIntegerValue()` method. – finnw Jul 08 '10 at 15:02

score 0 · Answer 2 · answered Jul 08 '10 at 14:47

You could try something like this

BigFraction fraction = ...

BigInteger num = fraction.getNumerator();
BigInteger den = fraction.getDenominator();
BigInteger[] divideAndReminder = num.divideAndRemainder(den);

Then finally

BigInteger integralPart = divideAndReminder[0];

score 0 · Answer 3 · answered Jul 08 '10 at 14:47

0

This should do the trick.

bigInteger = bigFraction.genNumerator().divide(bigFraction.getDenominator());

answered Jul 08 '10 at 14:47

torak

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Get the integral part of a BigFraction, as a BigInteger

3 Answers3