Please don't mark this question as duplicate as I have already seen the other questionSum of digits
Well, I have a following code
string = "2x83u0x7u8i9lkueieueue8"
numeric = lambda x: int(x) if x.isdigit() else 0
print reduce(lambda x, y: x + numeric(y), string , 0)
The answer should be 2 + 83 + 0 + 7 + 8 + 9 + 8 = 117 and not 45
The simplest way is to use a regex:
import re
string = "2x83u0x7u8i9lkueieueue8"
print(sum(map(int, re.findall("\d+", string))))
"\d+" finds 1 or more digits, so we just map the resulting list of string digits to int and sum
reduce() always operates on each item in an iterable individually. In this case, that means that the substring "83" is treated by your code as the integer 8 and the integer 3, not 83. You need to change your approach if you want to correctly handle multi-digit values.
