Check exit status of function with itself exit status

Question

I have a function ff in 1.sh with exit status 33. When I call this function in 2.sh and call function ff and if the exit status is 33, then my 2.sh is broken. How can I do a continue step? like this:

if [ exit_of_ff -ne 0 ]
then
 continue
fi

I don't understand your specific question. Please be more precise, and make an effort to use well-constructed sentences to convey your problem. — Andras Deak -- Слава Україні, Aug 14 '15 at 14:07
@BertrandMartel I'm guessing he doesn't want his 2.sh to break, but rather catch the exit and continue working — akalikin, Aug 14 '15 at 14:12

score 1 · Answer 1 · answered Aug 14 '15 at 14:12

Not really an answer but a formatted comment.

If you have

ff() {
    if [ some_condition ]; then
        return 33
    fi
    return
}

Then, normally to check the error condition, you would do

if ! ff; then
    echo function ff returned non-zero
    exit
fi
echo function ff returned success

If you want to store the return status

ff
status=$?
if [[ $status -eq 33 ]]; then ...

score -1 · Answer 2 · answered Aug 14 '15 at 14:28

-1

I solved this issue like this:

if ( ff $parameter ) then ff $parameter fi

in ff I have 3 parameters which are not accessible after ( )

answered Aug 14 '15 at 14:28

avsun

1
1

Check exit status of function with itself exit status

2 Answers2