JQuery Deferred rejection

Question

I'm trying to do this:

sendDetails(formData).done(checkErrors).done(nextForm);

Where sendDetails returns a JQuery.ajax(...) object

and checkErrors for now is

function checkErrors(data) {
    $.Deferred().reject();
}

I was under the assumption that this would prevent the call to nextForm, but it doesn't - what am I missing?

Using jQuery 1.11

Possible duplicate of: http://stackoverflow.com/questions/16335597/jquery-deferred-cancel-progress — R.A. Lucas, Aug 01 '15 at 02:50

score 0 · Answer 1 · answered Aug 01 '15 at 02:51

The documentation here at http://api.jquery.com/deferred.done/ says:

Since deferred.done() returns the deferred object, other methods of the deferred object can be chained to this one, including additional .done() methods.

If I understand your question, I think that answers your question. Hope this helps.

score 0 · Answer 2 · edited May 23 '17 at 11:43

0

jQuery deferred: cancel progress has the answer. Basically .done returns a deferred object, not a promise, so you can't cancel the subsequent call from the first call.

sendDetails(formData).then(checkErrors).done(nextForm);

works as anticipated

edited May 23 '17 at 11:43

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answered Aug 01 '15 at 02:57

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JQuery Deferred rejection

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