How can i get then "=" Php parse

Question

I need help on php. I get full link with this code

$url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

My link output is: http://localhost/Mid/photo-gallery/photos.php?ref=3%20%20ID=3 How can i get "3" ? I need last number. This number can be 3 digits. So maybe can be 444.

Why not `$_GET['ref']` or `$_GET['ID']`? – Sougata Bose Jul 31 '15 at 09:50 — Sougata Bose, Jul 31 '15 at 09:50
$_GET['ID'] is null. But problem is solved. Thank you – cimicimi Jul 31 '15 at 10:45 — cimicimi, Jul 31 '15 at 10:45

score 1 · Accepted Answer · answered Jul 31 '15 at 10:02

1

you can do it by using the following code.It will work for you.

  $url = " http://localhost/Mid/photo-gallery/photos.php?ref=3%20%20ID=3 ";
  $urls = explode("ID=",$url);  
  echo $urls[1];

answered Jul 31 '15 at 10:02

stackers

score 0 · Answer 2 · answered Jul 31 '15 at 09:58

0

You can try something like that:

$idVal = substr(strrchr($url, "="), 1);

It will return everything after the last equal. You have to be sure that ID will always be your last get parameter in your URL though.

answered Jul 31 '15 at 09:58

Matthieu

2 Answers2