I am getting ';' expected error,illegal start expression and else without if

Question

i want to out put like this-

150 can be fitted in:

short
int
long

150000 can be fitted in:

int
long

1500000000 can be fitted in:

int
long

213333333333333333333333333333333333 can't be fitted anywhere.

-100000000000000 can be fitted in:

long

import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
    byte b;
    long l;
    int t, v;
    int[] n;
    Scanner in=new Scanner(System.in);
    System.out.println("Inter the number");
    v=in.nextInt();
    n=new int[v];
    int i=0;
    while(n.hasNextInt())
        {
        n[i]=in.nextInt();
        i++;
    }
    for(int k=0;k<t;k++)
        {if(b<n[k])
          {  
            System.out.println(k+"this is fit in");
            System.out.println("*short");
            System.out.println("*int");
            System.out.println("*long");}
         else if(t==n[k]){
            System.out.println(n[k]+"this is fit in");
            System.out.println("int");
         System.out.println("long");}
        else if(t<=n[k]){
            System.out.println(n[k]+"this is fit in");
            System.out.println("int");
            System.out.println("long");}
        else if((t<=n[k])&&(l==n[k])){
            System.out.println(n[k]+"this is fit in");
            System.out.println("long");}
        else{
            System.out.println(n[k]+"this not fitted any where");}}}}

*My eyes!* Why in heaven's name would you hide the `}` at the end of the last statement in a block? Why? Why? — T.J. Crowder, Jul 23 '15 at 16:26
Please use correct grammar and formatting to make your question more readable. — VC1, Jul 23 '15 at 16:31

T.J. Crowder · Answer 1 · 2015-07-23T16:50:03.243

0

I expect it's the fact you have no logical join (&& or ||) and value here:

else if(t<=n[k]>){
// ------------^

Also note that the type int[] has no hasNextInt method, so this line:

while(n.hasNextInt())

won't compile (as n is int[]).

There are about a half dozen other logic errors in there (using uninitialized variables, etc.), but hopefully that gets you headed the right way.

edited Jul 23 '15 at 16:50

answered Jul 23 '15 at 16:28

T.J. Crowder

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score 0 · Answer 2 · answered Jul 23 '15 at 16:42

0

A quick fix is to use an IDE like eclipse or netbeans that formats your code and makes life far easier to debug, develop in open-source and reduces the development time. Coming to the errors: I can spot that you have missed a } at the end of the program script and I notice a syntactically wrong statement:

} else if (t <= n[k] > ) {

Please confirm to correct syntactically code and use formatting to enable fellow developers help you. Good luck!

answered Jul 23 '15 at 16:42

Nagabhushan Baddi

1,164
10
18

No, there is no missing `}` in the code. Yes, there is a problem with that line -- which I pointed out 20 minutes ago. – T.J. Crowder Jul 23 '15 at 16:48

I am getting ';' expected error,illegal start expression and else without if

2 Answers2