Python 3.4 while loop increment

Question

  x = Flase
  while !x :
     a = 0
     print(a)
     a++
     pass
     if a == 10:
       x = True
    else:
       continue

I get an error at "a++". I a using visual studio 2013 community and it gives me a red underline after "a++" and just before "pass"

possible duplicate of [Python integer incrementing with ++](http://stackoverflow.com/questions/2632677/python-integer-incrementing-with) — Matthew Read, Jul 21 '15 at 04:44
Please check your spelling before asking questions. a++ is an invalid python syntax. Use a += 1 instead. !x is an invalid python syntax as well. Use not x instead. Remember python is not Java or C#. — Eddie, Jul 21 '15 at 04:55

0xtvarun · Answer 1 · 2015-11-06T21:05:01.383

2

Python does not support ++. you can do this

     a = a + 1

edited Nov 06 '15 at 21:05

answered Jul 21 '15 at 04:53

0xtvarun

698
6
18

score 0 · Answer 2 · edited Jul 21 '15 at 06:13

There is no syntax like ++ or -- in Python, but you can do += 1 and -= 1.

And there are some logical error in your program

x = False
a = 0  # a should be initialized here. If it is initialized in loop it will be a never-ending loop
while not x :

   print(a)
   a+=1
   if a == 10:
     x = True
   else:
     continue

Notes:

check the spelling on False you have written it wrong
there is no need for pass
instead of using ! you should use not in Python

A simpler and more pythonic way is to use for and range:

for a in range(10):
    print(a)

Python 3.4 while loop increment

2 Answers2