How does mentioning multiple arithmetic operation within two operands work in Java

Question

I have an expression in my code -
int i = 10 + + 11 - - 12 + + 13 - - 14 + + 15;
The value of the variable 'i' evaluates to 75, which is the sum of all the integers mentioned in the expression. How does the evaluation happen in this scenario?

No one should ever write code like this. – duffymo Jul 16 '15 at 15:27 — duffymo, Jul 16 '15 at 15:27

score 10 · Accepted Answer · answered Jul 16 '15 at 13:40

10

this evaluate as

int i = 10 + (+ 11) - (- 12) + (+ 13) - (- 14) + (+ 15);

evaluate to

int i= 10 +11+12+13+14+15;

and all become + so value is 75.note - -is +

answered Jul 16 '15 at 13:40

Madhawa Priyashantha

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score 0 · Answer 2 · answered Jul 16 '15 at 13:41

0

First all unary operator will be evaluated. Ex: - - 10 = +10.

Rest you can evaluate now.

answered Jul 16 '15 at 13:41

Sachin Chandil

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How does mentioning multiple arithmetic operation within two operands work in Java

2 Answers2