Defining XmlRoot and typeof it with a variable?

Question

[XmlRoot("ConfigurationRoot")]
public class XmlDBConfiguration
{
    [XmlArray("Customers")]
    [XmlArrayItem("Customer", typeof(Customer))]

    public ArrayList _customers;
    private Dictionary<string, Customer> _customerDictionary;}

Is it possible to define the Element Name (in my case it is ConfigurationRoot) with a variable from another static class or any other way? I want to define my class that is going to be serialized (in my case it is Customer) as well. Is it possible to put a variable there and change it when I create an instance of that ?

Thanks in advance

score 2 · Answer 1 · answered Jun 29 '10 at 17:03

2

Yes, you can do that by using the XmlSerializer constructor that takes a XmlAttributesOverrides object. Providing your own XmlRootAttribute is explicitly supported. It is all well explained in the MSDN Library topic.

answered Jun 29 '10 at 17:03

Hans Passant

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score 1 · Accepted Answer · answered Jun 29 '10 at 17:04

1

I don't think you can change the value of the XmlRoot attribute on your class. You can however specify an override of this attribute when you create XmlSerializer - just use this constructor: http://msdn.microsoft.com/en-us/library/f1wczcys.aspx

answered Jun 29 '10 at 17:04

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Defining XmlRoot and typeof it with a variable?

2 Answers2