Getting a none type error while iterating a dictionary?

Question

Code:-

def displayHand(hand):
    for letter in hand.keys():
       for j in range(hand[letter]):
         print letter,              # print all on the same line
    print                               # print an empty line

hand = {'a':1, 'q':1, 'l':2, 'm':1, 'u':1, 'i':1}

print displayHand(hand)

Output:-

a i m l l q u
None

Req Output:-

a i m l l q u

Kindly give a logical solution.

Did you `print displayHand(hand)` anywhere? – Malik Brahimi Jul 14 '15 at 14:24 — Malik Brahimi, Jul 14 '15 at 14:24
yes see the edit sir – salil vishnu Kapur Jul 14 '15 at 14:24 — salil vishnu Kapur, Jul 14 '15 at 14:24

score 3 · Answer 1 · answered Jul 14 '15 at 14:27

displayHand returns nothing. Just remove the print of the end of your code and it will work.

def displayHand(hand):
    for letter in hand.keys():
       for j in range(hand[letter]):
         print letter,              # print all on the same line
    print                               # print an empty line

hand = {'a':1, 'q':1, 'l':2, 'm':1, 'u':1, 'i':1}

displayHand(hand)

Output:

a i m l l q u

Malik Brahimi · Accepted Answer · 2015-07-14T14:32:47.183

1

Your function does not return anything thus when you print the result of the function it prints None

displayHand(hand) # execute the function without printing the result, in this case None

edited Jul 14 '15 at 14:32

answered Jul 14 '15 at 14:25

Malik Brahimi

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score 1 · Answer 3 · answered Jul 14 '15 at 14:26

1

displayHand() function does not return anything, hence when you do -

print displayHand(hand)

This actually prints None , since displayHand() did not return anything. Just call it as normal without the print -

displayHand(hand)

answered Jul 14 '15 at 14:26

Anand S Kumar

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Getting a none type error while iterating a dictionary?

3 Answers3