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I have a website siavoush-re.co.uk which is linked to my Instagram account using Instafeed.js. To use instafeed.js I have to create a new instance of it with properties of my choosing. I am trying to add a property to the instance depending on the screen size using an if statement, here is what I have done so far,

var feed = new Instafeed({
    get: 'user',
    userId: private,
    limit: 21,
    accessToken: 'private',

});

if (document.documentElement.clientWidth > 600 ) {
    feed.resolution = 'low_resolution';
};

feed.run();

I am new to javascript, what would be the correct implementation?

Sai
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1 Answers1

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Your syntax is correct, but I think this is what you intended:

feed.options.resolution = 'low_resolution';

In terms of JavaScript, the approach you had was totally valid. But the Instafeed.js library you mentioned stores all of the configuration values on a nested options property.

Steven Schobert
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