7

My current code looks like this:

pub trait A {}
pub trait HasA {
    type A: A;
    fn gimme_a() -> Self::A;
}

pub trait RichA: A {}
pub trait RichHasA: HasA {
    type A: RichA;
    fn gimme_a() -> Self::A;
    // ... more things go here ...
}

pub fn main() {}

My goal is to be able to use RichHasA as a HasA. The above code fails to compile with:

error[E0221]: ambiguous associated type `A` in bounds of `Self`
  --> src/main.rs:10:21
   |
3  |     type A: A;
   |     ---------- ambiguous `A` from `HasA`
...
9  |     type A: RichA;
   |     -------------- ambiguous `A` from `RichHasA`
10 |     fn gimme_a() -> Self::A;
   |                     ^^^^^^^ ambiguous associated type `A`

which makes sense. How can I disambiguate associated types?

Shepmaster
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ynimous
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1 Answers1

10

You can use what is called Fully Qualified Syntax (FQS):

fn gimme_a() -> <Self as HasA>::A;
fn gimme_a() -> <Self as RichHasA>::A;

See also:

Shepmaster
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