How to pass form model via GET in Yii 1.x

Question

How I can create URL to Yii form with existing model parameters in URL?

E.g. I have $model with some attributes and want get URL like this:

controller/formaction?Form%5Battr1%5D=VAL1&Form%5Battr2%5D=VAL2

score 0 · Answer 1 · answered Jul 06 '15 at 04:45

0

There is no way to customize the url when you are using GET method. When you use GET method, browser always concatenates name and value of all inputs with your form action string. So it can't be changed. One possible solution for getting ride of ugly urls, is using POST instead of GET.

answered Jul 06 '15 at 04:45

hamed

7,939
15
60
114

I don't want to change the submitted url of form. I just want create url to the form in another action with attributes in my Form model `$model`. E.g. when I use createUrl function (`$this->createUrl('formaction', $model)`) I get the result like this: `controller/formaction?attr1%5D=VAL1&attr2%5D=VAL2` and it doesn't parsed correctly in `formaction`. – elyzov Jul 06 '15 at 04:54

score 0 · Answer 2 · answered Jul 15 '19 at 14:26

0

You can generate such URLs in this way:

Yii::app()->createUrl('controller/formaction', [
    CHtml::activeName('Form', 'attr1') => 'VAL1',
    CHtml::activeName('Form', 'attr2') => 'VAL2',
]);

answered Jul 15 '19 at 14:26

rob006

21,383
5
53
74

score -1 · Answer 3 · answered Jul 15 '19 at 13:51

-1

Have you try something like this :

public function action formaction(){
  $form = Yii::app()->request->getQuery('Form',false);
}

answered Jul 15 '19 at 13:51

Renziito

78
3

How to pass form model via GET in Yii 1.x

3 Answers3