Assembly language x86 to machine code : which come first displacement or immediat data

Question

i wanna get the machine code for this instruction : MOV[BX+3465H],6754H.

the code of "MOV immediate to memory" is : 1100,011w and w=1 cuze we are on 16 bits so the first byts is 1100,0111.

for the 2nd its MOD reg r/m and mod=10, reg=000, r/m= 111.which means 1000,0111.

Here is my question : for the 3rnd and the 4th, do i have to start by 3465H which is the displacement or by 6754H the "Immediate data"? thanks.

why dont you just assemble it and then look at the result? – old_timer Jul 05 '15 at 16:35 — old_timer, Jul 05 '15 at 16:35

score 1 · Accepted Answer · answered Jul 05 '15 at 08:41

1

Displacement comes first, as shown in the manual:

format

answered Jul 05 '15 at 08:41

harold

1 Answers1