How to programmatically get content type name in Drupal 8

Question

I'm working on Drupal 8. And I want to get content type machine name and label. Here is my code:

$cont_type = node_type_get_types();
foreach ($cont_type as $key => $value) {
  $label = $value->name;
  $machine_name = $key;
}

Here I got an error message : Cannot access protected property Drupal\node\Entity\NodeType::$name

Jose D · Answer 1 · 2016-05-31T11:24:01.213

17

In order to get current content type:

$node = \Drupal::routeMatch()->getParameter('node');
$typeName = $node->bundle();
$typeLabel = $node->getTitle();

There is an alternative method.

$node = \Drupal::request()->attributes->get('node')

edited May 31 '16 at 11:24

answered May 31 '16 at 10:58

Jose D

489
3
5

Welcome Jose! Try to explain what your code does to make it a better answer! You should read this http://stackoverflow.com/help/how-to-answer – David May 31 '16 at 11:07

score 9 · Answer 2 · answered Apr 29 '16 at 13:06

9

<?php
  use Drupal\node\Entity\NodeType;
?>

<?php
  $all_content_types = NodeType::loadMultiple();
  /** @var NodeType $content_type */
  foreach ($all_content_types as $machine_name => $content_type) {
    $label = $content_type->label();
  }
?>

answered Apr 29 '16 at 13:06

ebeyrent

413
5
7

score 4 · Answer 3 · answered Jun 22 '22 at 13:29

4

Solved using this code in template_preprocess_node()

$content_type = $node->type->entity->label();

answered Jun 22 '22 at 13:29

Thirsty Six

399
1
6
13

score 1 · Answer 4 · answered Aug 09 '22 at 19:44

1

$entityTypeManager = \Drupal::service('entity_type.manager');

$types = [];
$contentTypes = $entityTypeManager->getStorage('node_type')->loadMultiple();
foreach ($contentTypes as $contentType) {
  $types[$contentType->id()] = $contentType->label();
}

answered Aug 09 '22 at 19:44

Mohammad Seifi

11
2

score 0 · Answer 5 · answered Jul 29 '15 at 13:10

0

The NodeType class inherits the label() method from the Entity class, use that function to get the content type label. See Entity::label.

$label = $value->label();

answered Jul 29 '15 at 13:10

baikho

5,203
4
40
47

score -1 · Answer 6 · answered Jun 06 '19 at 06:09

-1

use {{ node.field_name.fieldDefinition.label }}

answered Jun 06 '19 at 06:09

Sunnysinh Thakor

1
3

While this code may solve the question, [including an explanation](//meta.stackexchange.com/q/114762) of how and why this solves the problem would really help to improve the quality of your post, and probably result in more up-votes. Remember that you are answering the question for readers in the future, not just the person asking now. Please [edit] your answer to add explanations and give an indication of what limitations and assumptions apply. – Yunnosch Jun 17 '21 at 07:48

score -3 · Answer 7 · answered May 28 '19 at 09:50

-3

Please use the namespace

use Drupal\node\Entity\Node;

answered May 28 '19 at 09:50

Rahulmon Johnson

1

This is not an answer – AlxVallejo May 13 '20 at 21:16

How to programmatically get content type name in Drupal 8

7 Answers7