Quite simply you convert from a pointer to a reference by providing a concrete instance, i.e. you dereference:
void f(int& i);
f(*(new int)); // do not do this!
The problem is that raw pointers in C++ are precisely that - they do not have automatic lifetime scope, and by converting to an lvalue reference, you have suggested a contract that the instance is concrete and should not be destroyed by the receiver.
int* ptr = new int;
f(ptr);
delete ptr; // otherwise it leaked
Modern C++ uses RAII to provide controlled automatic lifetime management, and C++11 introduced unique_ptr
and shared_ptr
for handling pointers. With C++14 we also have the mechanisms to avoid raw pointers entirely.
std::unique_ptr<int> ptr = std::make_unique<int>(/* ctor arguments here */);
f(ptr.get());
// now when ptr goes out of scope, deletion happens automatically.
See also http://en.cppreference.com/w/cpp/memory/unique_ptr
Only one std::unique_ptr
should have the address of a given allocation at any time (it assumes ownership and will delete
the allocation on exiting scope if it's not release
d).
For a ref-counted pointer: http://en.cppreference.com/w/cpp/memory/shared_ptr
--- EDIT ---
Based on the OPs comments:
Firstly note that
Pair p = { "one", "two" };
// and
Pair p("one", "two");
Pair p{"one", "two"};
are synonymous, in all cases they create a stack-local variable, p
, by allocating stack space and calling Pair::Pair("one", "two")
to construct a Pair
object there.
Remember, however, that this is a stack variable - it has an automatic lifetime and will expire at the end of the current scope.
{ Pair p{"one", "two"}; list_add(list, p); } //p is destroyed
In theory, you can replace this with
list_add(list, Pair{"one", "two"});
But what matters is whether list_add
expects you to keep the object around until you remove it from the list... That is often what a list-based function that takes a pointer is expecting. If it takes a non-const reference, it may do the same.
To answer your original post::
struct A { virtual void doSomething() {} };
struct B : public A { virtual void doSomething() override() {} };
void useDoSomethingInterface(A& a) {
a.doSomething();
}
int main() {
A a;
B b;
useDoSomethingInterface(a);
useDoSomethingInterface(b);
}
consider the following:
void list_add(IList& list, Pair& pair) {
pair.next = list.head;
list.head = &pair; // << BAD NEWS
}
void badness(IList& list) {
list_add(list, Pair("hello", "world"));
}
void caller() {
IList list;
badness(list);
// list.head now points to a destroyed variable on the stack
C-pointers in C++ are raw, machine level pointers. They don't ref count. And C++ object instances have a fixed well defined lifetime: till the end of the scope.
However, if list_add
is taking its data by value
void list_add(IList& list, Pair pair)
Then we'll be ok. The temporary Pair we create will have to be copied once to create pair
and then copied again into the list, which is a shame but at least it won't crash.