PHP - call to a variable static method using the scope resolution operator

Question

I would like to call to a static method in such a way that class name and method name are variables.

Example:

class QQQ {
   public function www($x) {
      echo $x;
   }
}

$q = 'QQQ';
$w = 'www';

$q::$w(7); // this is what I am trying to do but it throws an error.

Thoughts?

you have not defined $x, that's why the error – Siim Kallari Jun 28 '15 at 12:13 — Siim Kallari, Jun 28 '15 at 12:13
I put something instead of $x, same error. – daryqsyro Jun 28 '15 at 12:14 — daryqsyro, Jun 28 '15 at 12:14
Your method is **not static**! – Rizier123 Jun 28 '15 at 12:16 — Rizier123, Jun 28 '15 at 12:16
what kind of error it throws? – Siim Kallari Jun 28 '15 at 12:19 — Siim Kallari, Jun 28 '15 at 12:19
function name must be a string... – daryqsyro Jun 28 '15 at 13:12 — daryqsyro, Jun 28 '15 at 13:12

score 0 · Answer 1 · answered Jun 28 '15 at 12:17

0

Just need to change

public function www($x) {

to

public static function www($x) {

Because, you are calling it by scope resolution operator :: so, it should be static OR you should change the way you are calling it

$test = new $q;

$test->$w(5);

Should work, depending on what you are trying to do with it.

answered Jun 28 '15 at 12:17

viral

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Can you please explain why? Directly calling QQQ::foo(7) does the work. But calling it $q::$w(7) says function name must be a string – daryqsyro Jun 28 '15 at 13:12

PHP - call to a variable static method using the scope resolution operator

1 Answers1