NSNumber with 0 convert to NSInteger/NSUInteger become nil

Question

Why NSNumber of 0 cannot be converted to correct NSInteger/NSUInteger value?

NSUInteger a = [@0 unsignedIntegerValue]; // a become nil

Why is a in the above line of code nil. Shouldn't it be equal to 0?

In the console:

(lldb) po [@0 intValue]
0

(lldb) po [@0 integerValue]
<nil>

(lldb) po [@0 unsignedIntegerValue]
<nil>

Update:

(lldb) p [@0 unsignedIntegerValue]
(NSUInteger) $0 = 0

score 3 · Accepted Answer · answered Jun 25 '15 at 09:15

3

Use p not po

(lldb) p [@0 integerValue]
(NSInteger) $1 = 0
(lldb) p [@0 intValue]
(int) $2 = 0
(lldb) p [@0 unsignedIntegerValue]
(NSUInteger) $3 = 0

answered Jun 25 '15 at 09:15

Leo

Thanks for reply. Clear myself, I'm assigning `@0` to a NSUInteger variable, and it turns out to be a `nil`. Is there any advise not to use NSInteger/NSUInteger? – Alston Jun 25 '15 at 09:19
[@0 integerValue] is not a object. You should use p value instead of po object – Hugo Aug 05 '15 at 06:39

1 Answers1