Do I get wrong output with BigDecimal ROUND_HALF_EVEN rounding?

Question

I have a problem with rounding of BigDecimal numbers using ROUND_HALF_EVEN as described here.

I want to round to 2 decimal places:

BigDecimal number1 = new BigDecimal("23.867995");
BigDecimal number2 = new BigDecimal("23.868");
Log.d("tag", number.setScale(2, BigDecimal.ROUND_HALF_EVEN) + ", " + );

Ouptut:

23.87

But the digit 6 is even, so it should be 23.86 or not?

The rounding would only be applicable for 23.865 which will go to even — leppie, Jun 24 '15 at 08:31
"round towards the "nearest neighbor" unless both neighbors are equidistant" — Michael Lang, Jun 24 '15 at 08:32
Your code doesn't compile. Which number are you rounding, number1 or number2? — Erwin Bolwidt, Jun 24 '15 at 09:27

score 1 · Answer 1 · answered Jun 24 '15 at 08:37

1

It's round half even, not round everything even. When a number is halfway between two options for what it could round to, it goes toward the even digit. If it's closer to one option than the other, it picks the closer option.

answered Jun 24 '15 at 08:37

user2357112

260,549
28
431
505

See the IEEE 754 Floating Point Standard of about one-third of a century ago. – Rick James Jun 28 '15 at 18:41

Do I get wrong output with BigDecimal ROUND_HALF_EVEN rounding?

1 Answers1