Split double-digit NSInteger into Two NSIntegers

Question

I am trying to figure out how to take a double-digit NSInteger on iOS (like 11) and turn it into 2 separate NSIntegers, each looking like "1". It will always be just 2 digits in the NSInteger, no more, no less, and no decimals.

score 2 · Accepted Answer · answered Jun 23 '15 at 04:27

2

You can simply use integer/modulo arithmetic

int tensDigit=originalNumber / 10;
int onesDigit=originalNumber % 10;

answered Jun 23 '15 at 04:27

Paulw11

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score 1 · Answer 2 · answered Jun 23 '15 at 04:35

1

NSInteger a=11;
NSInteger b=a%10;
NSInteger c=(a-b)/10;
NSLog(@"%@ %@ %@",a,b,c);

answered Jun 23 '15 at 04:35

Akshay Karanth

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Rizwan Shaikh · Answer 3 · 2015-06-23T04:38:56.707

0

use this it work (In Swift).

var number  = 36

var tenPlace = number / 10

var UnitPlace = number % 10

see the Screen shot.

enter image description here

edited Jun 23 '15 at 04:38

answered Jun 23 '15 at 04:34

Rizwan Shaikh

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You should put your actual code into your answer as it can be copied easily while a screenshot cannot – Paulw11 Jun 23 '15 at 04:36
Thanks for your advice – Rizwan Shaikh Jun 23 '15 at 04:43

score 0 · Answer 4 · answered Jun 23 '15 at 04:34

You can simply divide by 10 and find the reminder of division by 10.

NSNumber* number = [NSNumber numberWithInt:21];
NSNumber* partOne = [NSNumber numberWithInt:([number integerValue] / 10)];
NSNumber* partTwo = [NSNumber numberWithInt:([number integerValue] % 10)];

for 21, partOne will be 2 and partTwo will be 1.

In general, for any number n, ith digit is n % pow(10, i)

Split double-digit NSInteger into Two NSIntegers

4 Answers4