Remove the leading 0's till the decimal

Question

I want to remove the leading zeros in the decimal numbers.

So i want the output should be .324 not 0.324. I tried str.replaceFirst("^0+(?!$)", ""); Didn't work and i also tried the regex! No results! And yes I am working with BigDecimal.

Raman Shrivastava · Accepted Answer · 2015-06-20T23:24:12.353

4

Try this

str = str.replaceFirst("^0\\.", ".");

edited Jun 20 '15 at 23:24

answered Jun 20 '15 at 21:39

Raman Shrivastava

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26

can be shorter when using replaceFirst, which allows for a regex parameter: `str.replaceFirst("^0.", ".");` – Jo Oko Jun 20 '15 at 21:42
Hm I meant there is no need for the whole if-then-else construct. `str.replaceFirst("^0.", ".");` is completely sufficient because `^0.` only replaces `0.` when `str` is starting with `0.` and not for example with `10.` – Jo Oko Jun 20 '15 at 21:49
That's better. Thanks again. – Raman Shrivastava Jun 20 '15 at 21:51
It Worked! But still getting an error as the numbers are bigdecimals so on converting to string the result is of the exponential form! – Vishal Jun 20 '15 at 22:03
how are you converting it to string? – Raman Shrivastava Jun 20 '15 at 22:06
1

@RamanShrivastava: Now that you're using a regex instead of a literal string, you have to escape the dot to remove its special meaning: (`"\\."`). – Alan Moore Jun 20 '15 at 23:13
@Alan: You're absolutely correct. Correcting it. Thanks, – Raman Shrivastava Jun 20 '15 at 23:22

Amit.rk3 · Answer 2 · 2015-06-20T22:15:10.460

2

if you are trying to format BigDecimal having value 0.324 to .324. Then below works

    BigDecimal bd=new BigDecimal("0.23");// this will replace with your BigDecimal
    DecimalFormat df=null;
    //check if number is a fraction
    if(bd.remainder(BigDecimal.TEN).compareTo(BigDecimal.ZERO)>0)
      df=new DecimalFormat(".###");
    else
      df=new DecimalFormat("##");

    System.out.print(df.format(bd));// .format returns string as .23

0.23->.23
0->0
90->90
80.12->80.12

edited Jun 20 '15 at 22:15

answered Jun 20 '15 at 21:41

Amit.rk3

2,417
2
10
16

1

It then adds .0 to non-decimals! for e.g, 90 becomes 90.0 and 0 becomes .0 @Amit.rk3 – Vishal Jun 20 '15 at 21:50
@VishalSaini You can't have different formatting for same variable based on it's value. That is something which you have to handle in code, which is pretty easy. If I understand your requirement, you need this format only for decimals between 0 to 1. You can add simple if condition in your code to check if your value is lesser than one by `value.compareTo(BigDecimal.ONE)` . Then you can use above format, else use whatever is your existing format for other numbers greater than or equal to 1. – Amit.rk3 Jun 20 '15 at 22:00
Actually Sir! The numbers are greater than one! for e.g, 96.6 324.44 So i have to sort these numbers and then print in the sorted way! With decimals as .45 or .### – Vishal Jun 20 '15 at 22:05

Skaros Ilias · Answer 3 · 2015-06-20T21:45:09.257

0

do you want this for printing purposes? you wont be able to do any math using this, so i guess yes. then you could do:

BigDecimal number =new BigDecimal(0.254); 
       System.out.println(number.toString().substring(number.toString().indexOf("0.")+1));

output

.254000000000000003552713678800500929355621337890625

edited Jun 20 '15 at 21:45

answered Jun 20 '15 at 21:39

Skaros Ilias

1,008
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This will end up in a false result for some numbers. For example 1.24 will result in .24 as well. – Jo Oko Jun 20 '15 at 21:41
so true! updated answer, even thought it is getting messy now:) – Skaros Ilias Jun 20 '15 at 21:45

Remove the leading 0's till the decimal

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