Regular expression to match any characters including line breaks in a string using java

Question

I have a string which includes line breaks in java .I need a regular expression to match any characters including line breaks.

Here is the string:

String s= "Hello World".(line break)
       Note= amount"

I am using this (.*?) but it won't match line breaks.

You can use `"(?s).*` to match any character where `s` is for `DOTALL`. — anubhava, Jun 17 '15 at 09:06
You can always use a tool like regerx.com to test your regular expression. — Christophe De Troyer, Jun 17 '15 at 09:12

score 0 · Answer 1 · answered Jun 17 '15 at 09:21

0

You can try with this pattern:

([a-zA-Z\n])+

Tested on regexr. This is an example of how to implement it in Java

String pattern = "([a-zA-Z\n])+";
String input = "String with \n line break.";
Pattern p = Pattern.compile(pattern);
java.util.regex.Matcher m = p.matcher(input);

answered Jun 17 '15 at 09:21

IlGala

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I have a special characters – manzur Jun 17 '15 at 09:24
Look at [this](http://stackoverflow.com/questions/13946651/matching-special-characters-and-letters-in-regex) question for a complete explanation – IlGala Jun 17 '15 at 09:33

Regular expression to match any characters including line breaks in a string using java

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