How to get a int from a long double in java?

Question

I wanna do this math in java:

int index = 3 * (9568/20001);

in my calculator it shows 3 *( 0.47837608... ) which is 1.43512824..

but, In Java that always give me 0, even I were trying use format, or java.lang.Math.round.

The first postion int 1 of 1.43512824 is what I want to get.

With 3 integers you're doing integer math, try `3.0 * (9568/20001);`. — Kayaman, Jun 16 '15 at 06:38
@Kayaman Would still be `0`, as `9568/20001 == 0`, something like `3 * (9568d/20001d)` would work though — MadProgrammer, Jun 16 '15 at 06:43

score 1 · Answer 1 · edited Jun 16 '15 at 06:41

1

Try this

int index = (int)3 * (9568.0/20001);

Because an integer divided by an integer gives a integer in java thus your answer will not be accurate. If you write 9568.0/20001 it gives a double result and so result is more accurate.

edited Jun 16 '15 at 06:41

MadProgrammer

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answered Jun 16 '15 at 06:38

Sourav Kanta

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@MadProgrammer Yeah I was editting it . – Sourav Kanta Jun 16 '15 at 06:41
After re-reading, I think the OP wants `1`, so, yep – MadProgrammer Jun 16 '15 at 06:41
It is cool! thanks a lot! this is very quick fix! (int) 3*( (double) 9568/ (double) 20001) – HCOOLH Jun 16 '15 at 06:54
@HCOOLH you don't need to cast both of them to double,casting any one would do. The other one will automatically be type casted. – Sourav Kanta Jun 16 '15 at 06:57

How to get a int from a long double in java?

1 Answers1