Compile Lua Code and store the bytecode in a new file

Question

I know it is possible to compile the Lua code using LuaC as described here:

luac is the Lua compiler. It translates programs written in the Lua programming language into binary files that can be loaded and executed with lua_dofile in C or with dofile in Lua.

The problem is: I need to create an application in .Net (more specifically in C#) that will receive an input of multiple 'regular' *.lua files and then compile all of them to new files.

That's a link to **very** old lua documentation for the record. Are you asking how to do what luac does in your own code? Have you tried looking at the luac source? — Etan Reisner, Jun 12 '15 at 20:54
I'm wondering if is there a library that could do that for me... — Alexandre Severino, Jun 12 '15 at 20:55

score 2 · Answer 1 · answered Jun 13 '15 at 01:17

2

loadfile followed by string.dump does essentially what luac does.

answered Jun 13 '15 at 01:17

lhf

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score 0 · Answer 2 · answered Jun 12 '15 at 21:57

I ended up having to call LuaC.exe from inside my application.

My solution was doing the following:

string outFile = Path.GetDirectoryName(path) + "\\" + Path.GetFileNameWithoutExtension(path) + ".out";
System.Diagnostics.Process.Start(System.IO.Directory.GetCurrentDirectory() + "\\luac.exe", "-o \"" + outFile + "\" \"" + path + "\"");

path = outFile;

Compile Lua Code and store the bytecode in a new file

2 Answers2