I was solving this problem on spoj http://www.spoj.com/problems/ATOMS/. I had to give the integral part of log(m / n) / log(k) as output. I had taken m, n, k as long long. When I was calculating it using long doubles, I was getting a wrong answer, but when I used float, it got accepted.
printf("%lld\n", (long long)(log(m / (long double)n) / log(k)));
This was giving a wrong answer but this:
printf("%lld\n", (long long)((float)log(m / (float)n) / (float)log(k)));
got accepted. So are there situations when float is better than double with respect to precision?