How to use global object in Class

Question

I am wondering how to get the following to be a global function. I want the class function to not have to keep logging into the MySQL I am using

https://github.com/joshcam/PHP-MySQLi-Database-Class#initialization

This is what I have done so far, would that work?

<?php
require_once('system/MysqliDb.php');
$db = new MysqliDb ('host', 'username', 'password', 'databaseName');

class system{
  public function __construct() {
    $db;
 }

}
?>

score 1 · Answer 1 · edited Jun 05 '15 at 15:57

1

Pass in the database object using "dependency injection"

class system {
  protected $_db;
  public function __construct(MysqliDb $db){
    $this->_db = $db;
  }
}

edited Jun 05 '15 at 15:57

AbraCadaver

78,200
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answered Jun 05 '15 at 15:57

Spechal

2,634
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Sorry but that did not work the error I get is follows [Fri Jun 05 14:32:47 2015] [error] [client 49.199.36.167] PHP Catchable fatal error: Argument 1 passed to system::__construct() must be an instance of MysqliDb, none given, called in /home/my$ – RussellHarrower Jun 05 '15 at 18:31
That means you didn't pass it anything. Do you call it as new system($db) ... ? – Spechal Jun 05 '15 at 19:47

score 0 · Answer 2 · answered Aug 02 '15 at 09:03

0

I would suggest to use getInstance() method.

class system {
  protected $_db;
  public function __construct() {
    $this->_db = MysqliDb::getInstance();
  }
}

answered Aug 02 '15 at 09:03

alex b

24
3

How to use global object in Class

2 Answers2