A simple Script to extracting a zip file

Question

Good Evening all,

I think I'm not understanding the zipfile structure properly heres the code

import xbmc
import zipfile

targetzip = xbmc.translatePath('special://home/userdata/addon_data/plugin.program.tester/test.zip')
extractto = xbmc.translatePath('special://home/userdata/addon_data/plugin.program.tester/')

zip = ZipFile(targetzip)
zip.extractall(extractto)

Any Ideas why Its not working?

score 0 · Accepted Answer · answered Jun 02 '15 at 21:09

0

Try to do it this way

import zipfile

fh = open(targetzip, 'rb')
z = zipfile.ZipFile(fh)
for name in z.namelist():
    z.extract(name, extractto)
fh.close()

answered Jun 02 '15 at 21:09

Aleksander Monk

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With a few adjustments this was perfect Cheers Aleksander Monk – Simon Jeal Jun 02 '15 at 23:06
You can accept my answer if it was really helpful for you :) @SimonJeal – Aleksander Monk Jun 03 '15 at 06:21

score 0 · Answer 2 · answered Jun 02 '15 at 21:24

0

Try this code:

with zipfile.ZipFile(targetzip) as zf:
    zf.extractall(extractto)

answered Jun 02 '15 at 21:24

Delimitry

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A simple Script to extracting a zip file

2 Answers2