How to grep the logs between two time range

Question

I have a log file abc.log in which content is like this when I do a vi on it.

2015-05-28 18:12:00,815 INFO 0x7f6ed23e3700 send_to - recent: 1432861920 from dc:2 client_id: 102
2015-05-28 18:13:01,024 INFO 0x7f6ed23e3700 send_to - recent: 1432861980 from dc:2 client_id: 101
2015-05-28 18:13:42,244 WARN 0x7f6ed26e6700 mgr - Failed to upsert data for userid 3589109212161 with value cat and status -2
2015-05-28 18:14:00,135 INFO 0x7f6ed23e3700 send_to - recent: 1432862040 from dc:2 client_id: 103

I want to see the all the logs between this time frame:

2015-05-28 00:30:00 - 2015-05-28 02:30:00

So basically whatever logs I have between these time frame I want to see it in the same order in which it is there already. Is this possible to do using grep?

score 3 · Accepted Answer · edited Apr 13 '17 at 12:36

3

From what I understand AWK can be used for this. As well, there's an answer on Stack Overflow already that looks like exactly what you want?

https://unix.stackexchange.com/questions/123979/how-to-extract-logs-between-two-time-stamps

edited Apr 13 '17 at 12:36

Community

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answered May 29 '15 at 01:27

0X29A

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Thanks. In my case I don't have brackets around my date? How does awk script looks like then? – john May 29 '15 at 01:34
@david It is more than enough hints. You can easily get it if you know regular expression – SwiftMango May 29 '15 at 01:37

How to grep the logs between two time range

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