Read and Modify content of inner zip file using ZipInputStream

Question

I am trying to modify web.xml using ZipInputStream. File to read is web.xml which is inside ear/war file

C:/XX.ear/YY.war/WEB-INF/web.xml

ZipFile zipFile = new ZipFile("C:/XX.ear");
    Enumeration<? extends ZipEntry> entries = zipFile.entries();
    while(entries.hasMoreElements()){
        ZipEntry entry = entries.nextElement();
        if(entry.getName().equalsIgnoreCase("YY.war")){
            ZipInputStream inputStream = new ZipInputStream(zipFile.getInputStream(entry));
            ZipEntry zipEntry;
            while(( zipEntry  = inputStream.getNextEntry())!=null)
            {
                System.out.println(zipEntry.getName());// Prints WEB-INF/web.xml
                if (zipEntry.getName().endsWith(".xml")) {
                    ZipInputStream iStream = new ZipInputStream(zipFile.getInputStream(zipEntry)); 
                      // throws NullPointerException here

                }                   
            }                   
        }                       
    }

new ZipInputStream(zipFile.getInputStream(zipEntry)) I couldn't point to inner zip file to get input stream of inner war file

Is it possible to read the inner zipentry as inputstream ??

score 0 · Accepted Answer · edited May 23 '17 at 11:43

Java 7 nio2 package has a new file system interface and a new Zip File System provider. The interface and provider allow to traverse the zip tree in a visitor pattern style This should provide a more clear and efficient way to get to the inner zip file

Edit: I tried to traverse a zip-inside-zip and got an exception. according to this thread, you have to extract the inner zip in order to traverse it.

Read and Modify content of inner zip file using ZipInputStream

1 Answers1