Two constructors with same name different parameters entity framework

Question

I have a partial class Table1 which is generated by EF and I have created another partial class Table1 in the same namespace with the same name with some custom properties.

EF has created a parameterless constructor and I need to have one more constructor with some parameters in my custom partial class Table1. But my code is complaining:

member names cannot be the same as their enclosing type

Is there a workaround for this?

The EF generated code for Table1 looks like:

public partial class Table1
{
    public Table1()
    {
        this.something= new HashSet<something>();
    }
}

And my custom code for partial class Table1:

public partial class Table1
{
    public void Table1(string test)
    {
        //do something
    }
}

You will also get more eyes if you include a tag for which language you are using (after you post your code.) — Michael Dorgan, May 22 '15 at 22:52
Are you sure this is the **exact** code that declares your parametrized constructor? Did you declare `public void Table1(string test)`? — Bas, May 22 '15 at 22:59
Yes Bas, I had put void and that was the issue. Thanks for pointing my mistake! — user3557236, May 22 '15 at 23:05

score 1 · Answer 1 · answered May 23 '15 at 03:20

You do not need to put a return type on a constructor. You just need

public Table1(String test){ }

Not

Public void Table1(String test){

}

Your compiler is complaining because it thinks you are trying to declare a regular method with the same name as your constructor. Drop the void and it because a second constructor.

Two constructors with same name different parameters entity framework

1 Answers1