Generators are a powerful tool for organizing asynchronous code, but they don't magically wait for asynchronous code to run.
What's Happening
Let's walk through your code so you can see what is happening:
getRelationsList
is a generator function, that when called returns a new generator. At this point, no code in your generator function has been called (although if you were passing params they would be set). You then call .next
on your generator to start execution of the generator function. It will execute up until it hits the first yield statement and return an object with the yielded value and the completion status of the generator.
It seems you understand most of that so far, but generators do not magically transform the yielded out values. When you yield out db.relations.find({})
, you'll get the return value of the find
function which I'm assuming is a Promise or some type of thenable:
so your 'outside' value is { value:Promise, done:false }
The reason your inside console.log
never ran is that you're actually creating a new generator each time you call getRelationsList()
, so when you call getRelationsList().next()
again after the outside console.log
you're creating a new generator and calling next, so it only executes up to the first yield, just like the call on the previous line.
In order to finish execution you must call next twice on the same instance of your generator: once to execute up to the yield and once to continue execution to the end of the function.
var gen = getRelationsList()
gen.next() // { value:Promise, done:false }
gen.next() // { value:undefined, done:true } (will also console.log inside)
You'll notice, however, if you run this, the inside console.log
will be undefined
. That's because the value of a yield
statement is equal to the value passed to the following .next()
call.
For example:
var gen2 = getRelationsList()
gen2.next() // { value:Promise, done:false }
gen2.next(100) // { value:undefined, done:true }
Outputs
{ inside:100 }
Because we passed 100 to the second .next()
call and that became the value of the yield db.relations.find({})
statement which was then assigned to res
.
Here's a link demoing all of this: http://jsfiddle.net/qj1aszub/2/
The Solution
The creators of koa use a little library called co which basically takes yielded out promises and waits for them to complete before passing the resolved value back into the generator function (using the .next()
function) so that you can write your asynchronous code in a synchronous style.
co will return a promise, which will require you to call the .then
method on to get the value returned from the generator function.
var co = require('co');
var getRelationsList = function *() {
var res = yield db.relations.find({});
console.log({'inside: ': res});
return res
}
co(getRelationsList).then(function(res) {
console.log({'outside: ': res })
}).catch(function(err){
console.log('something went wrong')
});
co also allows you to yield out other generator functions and wait for their completion, so you don't have to wrap things with co at every level and deal with promises until you're at some sort of 'top level':
co(function *() {
var list = yield getRelationsList()
, processed = yield processRelations(list)
, response = yield request.post('/some/api', { data:processed })
return reponse.data
}).then(function(data) {
console.log('got:', data)
})