I'm actually using Crosswalk.
I have some hard restrictions about speaking about my project so i'll try to be as clear as possible.
When I open my app manually, Webview load the home index.html of the website.
But this website is used for WebRTC so, it send an invitation via an e-mail with specific URL.
- Is that possible to open my own application with URL that I just clicked ?
I checked for some <intent-filter>
but I have no clue how to deal with the URL opening.
Hope someone have some solutions or clues.
EDIT:
<intent-filter>
<data android:scheme="https" android:host="xxx.xxx.com"/>
<action android:name="android.intent.action.VIEW"/>
<category android:name="android.intent.category.BROWSABLE"/>
<category android:name="android.intent.category.DEFAULT"/>
</intent-filter>
With that I can open my application when I click on a link, but I still need to get the link url and set it as url loaded in my XWalkView.
Example:
https://xxx.xxx.com/join?xertfgf=1
When I click on that, my app open good, but know i want my XWalkView to load this.
Help :c