malformedURLException when declaring URL with string in Android

Question

According to Android reference you can declare an URL using a string.

That means that the next code is supposed to be correct(i.e):

 URL url = new URL("http://www.android.com/");

When I try to use it I get:

"java.net.MalformedURLException"

It happens to me on AndroidStudio 1.2.1.1

The full code I'm trying to use comes from the references of HttpURLConnect of Android:

 URL url = new URL("http://www.android.com/");
   HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
   try {
     InputStream in = new BufferedInputStream(urlConnection.getInputStream());
     readStream(in);
    finally {
     urlConnection.disconnect();
   }
 }

It's good, can you show me the complete code?, and what do you see when logging the getMessage() of the error? — theapache64, May 10 '15 at 18:40
Have you wrapped the code block with try-catch block which catch the MalFormedUrlException ? — theapache64, May 10 '15 at 18:44

score 2 · Accepted Answer · edited May 23 '17 at 11:51

Look at this:

Java Malformed URL Exception

The answer says: It is not raising the error, it's complaining that you haven't handled the possibility that it might, even though it won't, because the URL in this case is not malformed. Java seems to think this is a good idea. (It's not.)

To shut it up, add throws MalformedURLException or throws IOException to the method declaration. E.g.:

public void myMethod() throws IOException {
    URL url = new URL("https://wikipedia.org/");
}

score 2 · Answer 2 · answered May 10 '15 at 18:54

This works perfectly fine here

try {

    URL url = new URL("http://www.android.com/");
    HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();

    BufferedReader br = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
    String line;
    while ((line = br.readLine()) != null) {
        System.out.println(line);
    }

    urlConnection.disconnect();

} catch (Exception e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

malformedURLException when declaring URL with string in Android

2 Answers2