Your question is not 100% clear to me so I'm going to restate the problem to make sure my solution gets sense.
Problem
Get all documents where the message
property is of type object
or the message
property is a string and matches a particular regular expression (using the match
method).
Solution
You basically need an if
statement. For that, you can use the r.branch
to 'branch' your conditions depending on these things.
Here's a very long, but clear example on how to do this:
Let's say you have these documents and you want all documents where the message
property is an object or a string that has the substring 'string'. The documents look like this:
{
"id": "a1a17705-e7b0-4c84-b9d5-8a51f4599eeb" ,
"message": "invalid"
}, {
"id": "efa3e26f-2083-4066-93ac-227697476f75" ,
"message": "this is a string"
}, {
"id": "80f55c96-1960-4c38-9810-a76aef60d678" ,
"not_messages": "hello"
}, {
"id": "d59d4e9b-f1dd-4d23-a3ef-f984c2361226" ,
"message": {
"exists": true ,
"text": "this is a string"
}
}
For that , you can use the following query:
r.table('messages')
.hasFields('message') // only get document with the `message` property
.filter(function (row) {
return r.branch( // Check if it's an object
row('message').typeOf().eq('OBJECT'), // return true if it's an object
true,
r.branch( // Check if it's a string
row('message').typeOf().eq('STRING'),
r.branch( // Only return true if the `message` property ...
row('message').match('string'), // has the substring `string`
true,
false // return `false` if it's a string but doesn't match our regex
),
false // return `false` if it's neither a string or an object
)
)
})
Again this query is long and could be written a lot more elegantly, but it explains the use of branch
very clearly.
A shorter way of writing this query is this:
r.table('messages')
.hasFields('message')
.filter(function (row) {
return
row('message').typeOf().eq('OBJECT')
.or(
row('message').typeOf().eq('STRING').and(row('message').match('string'))
)
})
This basically uses the and
and or
methods instead of branch
.