How to define class type as param in func?

Question

I want to define enclosure method,which can goto an view controller like gotopage(currentController,TargetViewController,"targetidentify")

   class func gotoPage<T: UIViewController>(currentController:ViewController,targetControllerClass: T.Type,identify:String){
        var mTargetViewController:targetControllerClass  =  currentController.storyboard?.instantiateViewControllerWithIdentifier(identify) as! targetControllerClass
        currentController.showViewController(mTargetViewController, sender: currentController)
    }

Here is another similar question I have referenced. The question is as! targetControllerClass maybe not correct. and error while building: "targetControllerClass" is not a type. enter image description here How can I define this method with Class Type?

Possible duplicate from [here](http://stackoverflow.com/questions/24308975/how-to-pass-a-class-type-as-a-function-parameter). Might need to change to where the protocol exposes an init() method. — gjeck, May 06 '15 at 23:58
http://stackoverflow.com/questions/27711993/pass-type-to-generic-function-and-compare — matt, May 07 '15 at 00:10

gjeck · Accepted Answer · 2015-05-07T00:33:40.913

All view controllers will inherit from UIViewController, given that you can adjust your method as follows:

func gotoPage<T>(currentController: UIViewController, targetControllerClass: T.Type, identify: String) {
    var newController = currentController.storyboard?.instantiateViewControllerWithIdentifier(identify) as! UIViewController
    if newController is T {
        currentController.showViewController(newController, sender: currentController)
    }
}

You can then call it as follows:

gotoPage(self, targetControllerClass: UIPageViewController.self, identify: "test")

However, the addition of generics isn't very beneficial here.

Strange grammar with Generic. targetControllerClass seems is externalParameterName in here not localParameterName — Albert.Qing, May 07 '15 at 00:46

How to define class type as param in func?

1 Answers1