Type conversion to double value in java

Question

public class TypeConversion4 {

    public static void main(String[] args) {
        double d = 2D + 2d + 2. + 2l + 2L + 2f + 2F + 2.f + 2.D;
        System.out.println(d); //prints 18.0
    }
}

how it prints 18.0. Can anyone provide some analysis.

@kittu It's second-grader's multiplication (by repeated addition of the same number). — Sergey Kalinichenko, May 01 '15 at 09:16
@dasblinkenlight its not about multiplication. There are different types getting added — kittu, May 01 '15 at 09:20
@kittu For the purposes of adding, a two is a two, no matter what type. You add nine of them, and you get eighteen. `double` trumps everything else in your expression, so you get your eighteen as a `double` — Sergey Kalinichenko, May 01 '15 at 09:23
my bad as I got confused with the types getting added in the statement — kittu, May 01 '15 at 09:24
possible duplicate of [casting between short,int,long,double,float in Java](http://stackoverflow.com/questions/10516883/casting-between-short-int-long-double-float-in-java) — durron597, May 01 '15 at 15:03

score 1 · Accepted Answer · answered May 01 '15 at 09:17

1

So, what's the problem? All these twos converted to the biggest type while summing up and then the result casted to double. But you can store 2 in long, int, double and float without any error. That means that all you have to do is to sum these 9 twos and come up with 18.0.

answered May 01 '15 at 09:17

antonpp

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my bad as I got confused with the types getting added in the statement – kittu May 01 '15 at 09:24

Type conversion to double value in java

1 Answers1