How to preg_replace from indentifier to end of text with CR(LF) characters

Question

I'm trying to split a piece of text (actually html) into two pieces, a top and bottom part. An 'identifier' (<--#SPLIT#-->) in the text marks the position to split.

To get the upper part I have the following preg_replace that does work:

$upper = preg_replace('/<--#SPLIT#-->(\s*.*)*/', '', $text);

This leaves me with all the text that comes before '<--#SPLIT#-->'.

To get the lower part I came up with the following preg_replace that does NOT work correctly:

$lower = preg_replace('/(\s*.*)*<--#SPLIT#-->/', '', $text);

This returns an empty string.

How can I fix the second one?

Can you give a sample input and what you want outputted? This can probably be done with one regex. — chris85, Apr 29 '15 at 12:51
is there only one `<--#SPLIT#-->` in the text? And is `<--#SPLIT#-->` a literal string? — Casimir et Hippolyte, Apr 29 '15 at 12:58
Try this: $lower = preg_replace('/(.*)<--#SPLIT#-->/', '', $text); — splash58, Apr 29 '15 at 13:02

splash58 · Accepted Answer · 2015-04-29T19:31:16.260

1

It is better to use:

explode('<--#SPLIT#-->', $text);

Example code:

$text = 'Foo bar<--#SPLIT#-->Baz fez';
$temp = explode('<--#SPLIT#-->', $text);
$upper = $temp[0];
$lower = (count($temp > 1) ? $temp[1] : '');

// $upper == 'Foo bar'
// $lower == 'Baz fez'

edited Apr 29 '15 at 19:31

answered Apr 29 '15 at 19:06

splash58

26,043
3
22
34

Why didn't I think of that? Thanks. – Han Timmers Apr 29 '15 at 22:12

How to preg_replace from indentifier to end of text with CR(LF) characters

1 Answers1