StringUtils - Replace on the same line different words

Question

I read that using String.replaceAll is very slow. This how I do in old way:

String settence = "Java /*with*/ lambda /*expressions*/";
String replaceSettence = settence.replaceAll(Pattern.quote("/*with*/"), "is").replaceAll(Pattern.quote("/*expressions*/"), "future");

System.out.println(replaceSettence);

How can I do this with StringUtils in one line?

EDIT:

Thanks for the quick answers.

I use code provided by Steph. My conclusion is that replaceAll is must faster that StringUtils:

  Long startTime = System.currentTimeMillis();
        String settence = "Java /*with*/ lambda /*expressions*/";
        String replaceSettence = settence.replaceAll(Pattern.quote("/*with*/"), "is").replaceAll(Pattern.quote("/*expressions*/"), "future");

        System.out.println(replaceSettence + " " + (System.currentTimeMillis() - startTime));

        String settenceStringUtils = "Java /*with*/ lambda /*expressions*/";
        String replaceStringUtils = StringUtils.replaceEach(settence, new String[]{"/*with*/", "/*expressions*/"}, new String[]{"is", "future"});
        System.out.println(replaceStringUtils + "StringUtils-> " + (System.currentTimeMillis() - startTime));

@Reimeus , Exactly !! Goldbones will you provide source Where you read that ? — Neeraj Jain, Apr 27 '15 at 14:44
http://www.myhowto.org/under-the-hood/32-hidden-costs-of-using-java-string-methods/ — Goldbones, Apr 27 '15 at 14:50
You can't conclude with just one call of each functions. You have to make several iterations with differents keywords/sentences and compute the time average. — Steph, Apr 28 '15 at 07:41

score 3 · Accepted Answer · answered Apr 27 '15 at 14:44

3

Just like this:

String settence = "Java /*with*/ lambda /*expressions*/";
String replaceSettence = StringUtils.replaceEach(settence, new String[]{"/*with*/", "/*expressions*/"}, new String[]{"is","future"});
System.out.println(replaceSettence);

answered Apr 27 '15 at 14:44

Steph

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Is there any way to replace word Eg. text: "Princeton Group, Pa" => key:"inc", value:"" this will replace a substring and not a word – Syed Rafi Sep 01 '20 at 13:44
Yes, you can use space in regex to catch words. Or split your sentence by space and you will have an array of words so you are able to replace what you want. – Steph Sep 03 '20 at 07:10

StringUtils - Replace on the same line different words

1 Answers1