CharSequence defining multiple words?

Question

CharSequence listOfWords = ("word");

the code above successfully defines listOfWords as: "word" But I need listOfWorlds to have lots of words in it, not just the single "word".

CharSequence listOfWords = ("word")("secondword");

above code is what I want, but obviously incorrect.

I'd like to be able to call listOfWords and have it be defined as "word" OR "secondword". Is CharSequence even the correct variable here? Any help?

A `CharSequence` is a sequence of characters, like its name says; it won't "store" words. Also, if you look a little more carefully, you'll see that 1. methods of this interface are pretty much telling you that already, and 2. `String` implements `CharSequence`. — fge, Apr 26 '15 at 22:38

Shar1er80 · Answer 1 · 2015-04-26T22:48:34.800

You're probably better off using a List of String(s). For reference, http://docs.oracle.com/javase/7/docs/api/java/lang/String.html, you can see that String implements CharSequence

public static void main(String eth[]) {
    List<String> listOfWords = new ArrayList<>();
    listOfWords.add("word");
    listOfWords.add("secondWord");
    listOfWords.add("thirdWord");

    // You use your list as followed
    System.out.println(listOfWords.get(0)); // .get(0) gets the first word in the List
    System.out.println(listOfWords.get(1)); // .get(1) gets the second word in the List
    System.out.println(listOfWords.get(2)); // .get(2) gets the third word in the List
}

Results:

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@Tom Copy & Paste is a horrible thing :-)... Thanks – Shar1er80 Apr 26 '15 at 22:49 — Shar1er80, Apr 26 '15 at 22:49

CharSequence defining multiple words?

1 Answers1