I wanna ask some basic law of boolean algebra. What i learn is :
1. A+A'B=A+B
2. A+AB'=A+B'
3. A+AB=A
4. A+A'B'=A+B'
but i meet some condition like :
A'+AB
so, what is the answer for A'+AB
?
I wanna ask some basic law of boolean algebra. What i learn is :
1. A+A'B=A+B
2. A+AB'=A+B'
3. A+AB=A
4. A+A'B'=A+B'
but i meet some condition like :
A'+AB
so, what is the answer for A'+AB
?
Let's say A' = D
so when A
is false
, then D is true
and vice versa.
Then A' + AB = D + D'B
and if you understand your first equation:
D + D'B = D + B = A' + B
Regarding your comment:
I'll use this equality: AB + A'B = B
and I will combine the first with the third and the second with the fifth term:
x'y'z'+x'yz+xy'z'+xy'z+xyz = y'z' + yz + xy'z
Now, from the result, I can do this:
y'z' + yz + xy'z = yz + y'(z' + zx)
and now, using using A' + AB = A' + B
:
yz + y'(z' + zx) = yz + y'(z' + x) = yz + y'z' + y'x
or do this:
y'z' + yz + xy'z = y'z' + z(y+ xy') = y'z' + z(y + x) = y'z' + zy + xz
Are they different? No, take a look at this:
x y z | yz + y'z' + y'x | y'z' + zy + xz
0 0 0 | 1 | 1
0 0 1 | 0 | 0
0 1 0 | 0 | 0
0 1 1 | 1 | 1
1 0 0 | 1 | 1
1 0 1 | 1 | 1
1 1 0 | 0 | 0
1 1 1 | 1 | 1
You can use this open source project to solve basic boolean expression, its solve all the basic boolean expression