Addition of numbers - output

Question

I could not understand the exact computation logic here. How is 01234 being treated.

public static void main(String[] args) {
    System.out.println(01234 + 43210);
    System.out.println(1234 + 43210);
}

Output

43878
44444

possible duplicate of [09 is not recognized where as 9 is recognized](http://stackoverflow.com/questions/970039/09-is-not-recognized-where-as-9-is-recognized) — Hexaholic, Apr 24 '15 at 09:58

score 3 · Answer 1 · edited Apr 24 '15 at 10:04

3

A number literal starting with a leading zero is treated as octal (base 8). So 01234 is in fact 668 (decimal)

edited Apr 24 '15 at 10:04

Alex Salauyou

answered Apr 24 '15 at 09:59

Michel Billaud

score 1 · Accepted Answer · answered Apr 24 '15 at 09:58

1

How is 01234 being treated?

It is treated here as octal. Any number starting with 0 is octal.

answered Apr 24 '15 at 09:58

Masudul

2 Answers2