Spring prototype bean reference in Spring @Configuration

Question

I went through the following page to bootstrap an applicationContext.xml in Java.

http://docs.spring.io/spring-javaconfig/docs/1.0.0.M4/reference/html/ch06.html

My applicationContext has something like:

<beans>
    <bean id="foo" class="com.mypackage.Foo" scope="prototype">       
    </bean>
</beans>

I need to refer to "foo" in Java as follows:

@Configuration
@AnnotationDrivenConfig 
@ImportXml("classpath:applicationContext.xml")
public class Config {

    @Autowired Foo foo;

    @Bean(name="fooRepository")
    @Scope("prototype")
    public FooRepository fooRepository() {
        return new JdbcFooRepository(foo);
    }


}

I am creating a reference of FooRepository as follows:

ApplicationContext ctx = 
                   new AnnotationConfigApplicationContext(Config.class);

FooRepository fr = ctx.getBean("fooRepository", FooRepository.class);

Every time I invoke it, I get a new instance of FooRepository which is defined as "prototype" and this is fine with me.

But when an instance of FooRepository is returned I see the same instance of "foo" is used though "foo" in the XML file is "prototype".

How do I set Foo as new instance all the time to FooRepository when FooRepository is created?
The instance of Foo should be from the XML file.

why is foo annotated with `**prototype**` instead of `prototype`? http://www.tutorialspoint.com/spring/spring_bean_scopes.htm And can you provide the souce of Foo? is it annotated with something as well like Component? — Zarathustra, Apr 24 '15 at 05:12
I wanted to use the bold font for it. Actually it is just "prototype". I am editing it now... — serverfaces, Apr 24 '15 at 05:16

score 1 · Accepted Answer · edited May 23 '17 at 12:14

1

You need to remove the entry of Foo from xml. You can define it this way.

@Configuration
@AnnotationDrivenConfig
@ImportXml("classpath:applicationContext.xml")
public class Config {

    @Bean(name = "fooRepository")
    @Scope("prototype")
    public FooRepository fooRepository() {
        return new JdbcFooRepository(foo());
    }

    @Bean(name = "foo")
    @Scope("prototype")
    public Foo foo() {
        return new foo();
    }
}

Approach 2: You can refer this SO Answer.

@Configuration
@AnnotationDrivenConfig
@ImportXml("classpath:applicationContext.xml")
public class Config {

    @Autowired
    private ApplicationContext context;

    @Bean(name = "fooRepository")
    @Scope("prototype")
    public FooRepository fooRepository() {
        return new JdbcFooRepository(context.getBean("foo", Foo.class));
    }
}

edited May 23 '17 at 12:14

Community

1
1

answered Apr 24 '15 at 05:05

Naman Gala

4,670
1
21
55

Assuming that I don't have access to edit XML, still need to refer to the XML file to get Foo as prototype, is there a way? – serverfaces Apr 24 '15 at 05:09
I will give it a shot using approach #2 tomorrow morning and let you know. – serverfaces Apr 24 '15 at 05:18
@NamanGala Approach #1 should work since you are able to "override" the foo bean, Approach #2 will treat foo as singelton, so it does not. – Zarathustra Apr 24 '15 at 05:19
@Zarathustra, in approach 2 foo is defined as prototype in config xml file. So everytime it will fetch new object of foo. – Naman Gala Apr 24 '15 at 05:21
ah, I got it, since the @Configuration class itself is a singelton. – Zarathustra Apr 24 '15 at 05:23

Zarathustra · Answer 2 · 2015-04-24T05:44:41.510

-1

First Approach:

Foo should be an prototype as well.

Second Approach:

@Configuration 
@AnnotationDrivenConfig 
@ImportXml("classpath:applicationContext.xml") 
public class Config {

            @Bean(name = "fooRepository")
            @Scope(ConfigurableBeanFactory.SCOPE_PROTOTYPE)
            public FooRepository fooRepository(Foo foo) {
                return new JdbcFooRepository(foo);
            }
}

edited Apr 24 '15 at 05:44

answered Apr 24 '15 at 05:00

Zarathustra

2,853
4
33
62

Yes, Foo is prototype. Please see XML sample provided. – serverfaces Apr 24 '15 at 05:03

Spring prototype bean reference in Spring @Configuration

2 Answers2