How to grep rows that have value less than or equal to value

Question

size=139
size=9292
size=140
size=139
size=139
size=10213
size=139
size=140
size=11186
size=139
size=139
size=140
size=12342
size=139
size=139
size=140
size=11360

How can I grep rows that has greater value than 1000 from size.txt ?

Also, is there any way that I could find this information from entire folder, which has many txt files like this ?

Wintermute · Accepted Answer · 2015-04-18T10:03:29.900

With awk:

awk -F= '$2 > 1000' filename

This can be used with many file names:

awk -F= '$2 > 1000' *

Or combined with find to do it to subfolders as well:

find directory -type f -exec awk -F= '$2 > 1000' '{}' \;

For the latter two, it may be desirable to print the file name as well as the actual result (mimicking the behavior of grep), which could be achieved like this:

awk -F= '$2 > 1000 { print FILENAME ": " $0 }' *

score 2 · Answer 2 · answered Apr 18 '15 at 10:34

2

With bash builin commands:

while IFS="=" read variable value; do
  [[ $value -gt 1000 ]] && echo "${variable}=${value}"
done < file

Output:

size=9292
size=10213
size=11186
size=12342
size=11360

answered Apr 18 '15 at 10:34

Cyrus

84,225
14
89
153

score 0 · Answer 3 · answered Apr 18 '15 at 10:37

0

egrep "size=[0-9]{4}" size.txt

answered Apr 18 '15 at 10:37

Walter A

19,067
2
23
43

This would match `size=0001` – William Pursell Apr 18 '15 at 10:59
egrep "[1-9][0-9]{3}" | grep -v "=1000$" – Walter A Apr 18 '15 at 11:52

How to grep rows that have value less than or equal to value

3 Answers3